Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 1 - Problems - Page 37: 1.42

Answer

(a) $20^{\circ}C$, $293K$ (b) $109K$, $-263^{\circ}F$ (c) $-273^{\circ}C$, $-460^{\circ}F$

Work Step by Step

Recall our conversion formulas: $^{\circ}C=(^{\circ}F-32) * \dfrac{5}{9}$ $^{\circ}F =( ^{\circ}C * \dfrac{9}{5})+32$ $K = {^{\circ}C}+273$ $^{\circ}C = K-273$ $(a)$ $68^{\circ}C$ $^{\circ}C=(68^{\circ}F-32) * \dfrac{5}{9}$ $20^{\circ}C$ $K = {20^{\circ}C}+273$ $293K$ $(b) -164^{\circ}C$ $K = {-164^{\circ}C}+273$ $109K$ $^{\circ}F =(-164 ^{\circ}C * \dfrac{9}{5})+32$ $-263^{\circ}F$ $(c) 0K$ $^{\circ}C = 0K-273$ $-273^{\circ}C$ $^{\circ}F =( -273^{\circ}C * \dfrac{9}{5})+32$ $-460^{\circ}F$
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