Answer
(a) $9.626cm^3$
(b) $64.92g$
Work Step by Step
$(a)$
First, we subtract the weight of the empty vial from the full vial to get the weight of the mercury.
$185.56g - 55.32g = 130.24g$
We can multiply by the density to get the volume. $g$ cancels out to give us $cm^3$.
$130.24g *\dfrac{1cm^3}{13.53g}$
$$9.626cm^3$$
$(b)$
To find the weight of a vial of water, multiply the volume we calculated by the density of water $(d=0.997g/cm^3)$ and remember to add the weight of the empty vial itself.
$9.626cm^3 * \dfrac{0.997g}{cm^3} + 55.32g$
$$64.92g$$
