Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 7 - Periodic Properties of the Elements - Integrative Exercises - Page 296: 7.111a

Answer

$E=21.2\ eV$

Work Step by Step

$E=\frac{6.262\times10^{-34}\ J-s\times2.9998\times10^8\ m/s}{58.4\times10^{-9}\ m}=3.4015\times10^{-18}\ J/photon$ $\frac{3.4015\times10^{-18}\ J}{photon}\times\frac{1\ kJ}{1000\ J}\times\frac{6.022\times10^{23}\ photons}{mol}\times\frac{1\ eV-mol}{96.485\ kJ}=21.230=21.2\ eV$
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