Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 7 - Periodic Properties of the Elements - Exercises: 7.31b

Answer

The effective nuclear charge for the 2p electrons: $Z_{eff}(F^-)=7+$ and $Z_{eff}(Na^+)=9+$

Work Step by Step

The formula to calculate $Z_{eff}$ for the 2p electrons is $$Z_{eff}=Z-S$$ Z: the nuclear charge of the element S: the screening constant Both $F^-$ and $Na^+$ have 10 electrons and the same electron configuration: $1s^22s^22p^6$. That means for the 2p electrons, both have 2 core electrons and 8 valence electrons. Therefore, the screening constant $S$ of both $F^-$ and $Na^+$ for the 2p electrons is $$S=2\times1.00+8\times0.00=2.00$$ The nuclear charge of $F^-$ is $Z=9+$ The nuclear charge of $Na^+$ is $Z=11+$ Therefore, the effective nuclear charge of $F^-$ and $Na^+$ is $Z_{eff}(F^-)=(9+)-2.00=7+$ $Z_{eff}(Na^+)=(11+)-2.00=9+$
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