Answer
$2d_2-d1$
Work Step by Step
The X-X bond length is twice the atomic radii of X.
$r_X = d_2-\frac{d_1}{2}$
So the length of the X-X bond is:
$2(d_2-\frac{d_1}{2})=2d_2-d1$
Chemistry: The Central Science (13th Edition)
by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.
Published by
Prentice Hall
ISBN 10:
0321910419
ISBN 13:
978-0-32191-041-7
Chapter 7 - Periodic Properties of the Elements - Exercises - Page 290: 7.5b
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