#### Answer

This set is invalid in $m_s$.

#### Work Step by Step

*RULES TO REMEMBER:
- $n\gt0$ and $l\ge0$
- $l\lt n$
- $|m_l|\leq l$, which also means $m_l\leq l$
- There are only 2 possible values for $m_s$: $\frac{1}{2}$ and $-\frac{1}{2}$.
Here $m_s=0$, which is invalid because there are only 2 possible values for $m_s$, and $0$ is not one of them.