Chemistry: The Central Science (13th Edition)

$\Delta E = -44.1 kJ$ Exothermic
The system releases 66.1kJ of heat and the surroundings to 44kJ of work on the system. First we check table 5.1 to find the sign of q and w and find that q = - 66.1 kJ since the heat is leaving the system w = + 44kJ since work is done on the system Then we have $\Delta E = q+w = -66.1 kJ + 44kJ = -22.1 kJ$