Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Exercises: 5.25b

Answer

$\Delta E = -44.1 kJ$ Exothermic

Work Step by Step

The system releases 66.1kJ of heat and the surroundings to 44kJ of work on the system. First we check table 5.1 to find the sign of q and w and find that q = - 66.1 kJ since the heat is leaving the system w = + 44kJ since work is done on the system Then we have $\Delta E = q+w = -66.1 kJ + 44kJ = -22.1 kJ $
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