# Chapter 5 - Thermochemistry - Exercises: 5.25b

$\Delta E = -44.1 kJ$ Exothermic

#### Work Step by Step

The system releases 66.1kJ of heat and the surroundings to 44kJ of work on the system. First we check table 5.1 to find the sign of q and w and find that q = - 66.1 kJ since the heat is leaving the system w = + 44kJ since work is done on the system Then we have $\Delta E = q+w = -66.1 kJ + 44kJ = -22.1 kJ$

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