Answer
$\Delta E = -44.1 kJ$
Exothermic
Work Step by Step
The system releases 66.1kJ of heat and the surroundings to 44kJ of work on the system. First we check table 5.1 to find the sign of q and w and find that
q = - 66.1 kJ since the heat is leaving the system
w = + 44kJ since work is done on the system
Then we have $\Delta E = q+w = -66.1 kJ + 44kJ = -22.1 kJ $
