Answer
S$^{2-}$ --> SO$_{4}$$^{2-}$
In this reaction, S is oxidized.
Sulfur is oxidized in this equation because it is the reducing agent, which means it is losing electrons to the oxygen atom.
H${_2}$O${_2}$ --> H${_2}$O
In this reaction, O is reduced.
Oxygen is reduced in this reaction because it is the oxidizing agent, which means it is gaining electrons from the hydrogen atoms.
Work Step by Step
S$^{2-}$ --> SO$_{4}$$^{2-}$
In this reaction, S is oxidized.
Sulfur is oxidized in this equation because it is the reducing agent, which means it is losing electrons to the oxygen atom.
H${_2}$O${_2}$ --> H${_2}$O
In this reaction, O is reduced.
Oxygen is reduced in this reaction because it is the oxidizing agent, which means it is gaining electrons from the hydrogen atoms.
