Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 4 - Reactions in Aqueous Solution - Exercises: 4.26b

Answer

Net Ionic: $Ba^{+2}(aq)$ + $SO_{4}^{-2}(aq)$ $\rightarrow$ $BaSO_{4}(s)$ Spectator Ions: $K^{+}$ and $NO_{3}^{-}$

Work Step by Step

Barium (ii) bonds with Sulfate to form a solid precipitate while Potassium Nitrate is a spectator. So the complete ionic solution reduces from $Ba(NO_{3})_{2}(aq)$ + $K_{2}SO_{4}(aq)$ $\rightarrow$ $BaSO_{4}(s)$ + $2KNO_{3}(aq)$ to the net ionic shown above.
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