Answer
Net Ionic: $Ba^{+2}(aq)$ + $SO_{4}^{-2}(aq)$ $\rightarrow$ $BaSO_{4}(s)$
Spectator Ions: $K^{+}$ and $NO_{3}^{-}$
Work Step by Step
Barium (ii) bonds with Sulfate to form a solid precipitate while Potassium Nitrate is a spectator.
So the complete ionic solution reduces from
$Ba(NO_{3})_{2}(aq)$ + $K_{2}SO_{4}(aq)$ $\rightarrow$ $BaSO_{4}(s)$ + $2KNO_{3}(aq)$
to the net ionic shown above.
