## Chemistry: The Central Science (13th Edition)

$Kp = Kc(RT)^{\Delta n}$ If we have Kp = 3.423 then we need to find the value of $\Delta n$ 2SO$_2$(g) + O$_2$(g) 2SO$_3$(g) Sicne we have 3 moles on the left and 2 moles on the right, it means we have a $\Delta n$ of -1. Therefore, we have: $3.423 = Kc(RT)^-1$ R = 0.0821 and T = 1000K so we have RT = 82.1 and then Kc = 281.03