Answer
$8.00\times10^{-1}M/s$
Work Step by Step
$2NO(g)+O_2(g)->2NO_2(g)$
In the above chemical equation, since the coefficient of $NO$ is 2, its rate of disappearance is twice the rate of the reaction.
$rate=k[NO]^2[O_2]=(7.11\times10^3)\times(0.0750^2)\times(0.0100)=4.00\times10^{-1} M/s$
Therefore, the rate of dissapearance of $NO$ would be $8.00\times10^{-1}M/s$.
