Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 14 - Chemical Kinetics - Exercises - Page 619: 14.35d

Answer

$0.170 M/s$

Work Step by Step

$rate=k[BF_{3}][NH_{3}]$ As calculated, the rate constant is $3.408 M^{-1}*s^{-1}$ and is unchanged. $rate=3.408M^{-1}s^{-1} * 0.100 M * 0.500 M=0.170M/s$.
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