Answer
$0.170 M/s$
Work Step by Step
$rate=k[BF_{3}][NH_{3}]$
As calculated, the rate constant is $3.408 M^{-1}*s^{-1}$ and is unchanged.
$rate=3.408M^{-1}s^{-1} * 0.100 M * 0.500 M=0.170M/s$.
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