Answer
$3.408 M^{-1}*s^{-1}$
Work Step by Step
$rate=k[BF_{3}][NH_{3}]$
$k=\frac{rate}{[BF_{3}][NH_{3}]}=\frac{0.2130 M/s}{0.250M*0.250M}$ (from Exp#1).
$k=\frac{0.2130 M*s^{-1}}{0.0625M^2}=3.408 M^{-1}*s^{-1}$
Chemistry: The Central Science (13th Edition)
by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.
Published by
Prentice Hall
ISBN 10:
0321910419
ISBN 13:
978-0-32191-041-7
Chapter 14 - Chemical Kinetics - Exercises - Page 619: 14.35c
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