Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 10 - Gases - Exercises - Page 436: 10.51a

Answer

1.76 g/L

Work Step by Step

The formula is d = PM/RT. First we need the molar mass of NO2:Nitrogen is 14g/mol and O is 16g/mol so we have 14 + 2*16 = 46g/mol. Then we convert the 35C to Kelvin by adding 273, which is 308K. d = (0.970 atm * 46g/mol) / (0.0821 * 308K) = 1.76 g/L

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