Answer
The final concentration is equal to 0.100 M NaBr.
Work Step by Step
1. Write the dilution expression, and solve for the final concentration ($C_2)$:
$C_1 \times V_1 = C_2 \times V_2$
- Now, divide both sides by "$V_2$":
$\frac{C_1 \times V_1}{V_2} = C_2$
$C_2 = \frac{C_1 \times V_1}{V_2} $
2. Substitute the values and calculate the final concentration:
$C_2 = \frac{(0.200 \space M) \times (25.0 \space mL)}{50.0 \space mL} = 0.100 \space M$