Answer
18.0 g
Work Step by Step
$6.00\%(\text{m/v})$ is 6.00 g of KCl in 100. mL of solution.
Therefore, the mass in grams of KCl in 300. mL=
$300.\,mL\times\frac{6.00\,g}{100.\,mL}=18.0\,g$
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