Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 9 - Section 9.4 - Concentrations of Solutions - Study Check 9.9 - Page 300: 1

Answer

18.0 g

Work Step by Step

$6.00\%(\text{m/v})$ is 6.00 g of KCl in 100. mL of solution. Therefore, the mass in grams of KCl in 300. mL= $300.\,mL\times\frac{6.00\,g}{100.\,mL}=18.0\,g$
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