Answer
750 mL
Work Step by Step
Moles of solute=$\frac{\text{Mass in grams}}{\text{Molar mass}}=\frac{164\,g}{36.46\,g/mol}=4.498\,mol$
Molarity(M)=$\frac{\text{moles of solute(n)}}{\text{liters of solution(V)}}$
$\implies V=\frac{\text{n}}{\text{M}}=\frac{4.498\,mol}{6.0\,M}=0.750\,L=750\,mL$
