Answer
There are 2.00 moles of $O_2$ in 44.8 L of $O_2$ gas at STP conditions.
Work Step by Step
1. Setup the conversion factors:
For a gas at STP conditions, we can use the equality: $1 \space mole = 22.4 \space L$:
$\frac{1 \space mole}{22.4 \space L}$ and $\frac{22.4 \space L}{1 \space mole}$
2. Calculate the number of moles of $O_2$:
$44.8 \space L \times \frac{1 \space mole}{22.4 \space L} = 2.00 \space moles$
