Answer
The final volume is equal to 26.7 L
Work Step by Step
1. Using Avogadro's law, solve for "$V_2$":
$\frac{V_1}{n_1} = \frac{V_2}{n_2}$
- Multiply both sides by "$n_2$"
$\frac{V_1}{n_1} \times n_2 = {V_2}$
2. Since 3.50 moles of Ne atoms are added, the final number of moles is equal to "$n_1 + 3.50 \space moles$".
$n_2 = n_1 + 3.50 \space moles$
$n_2 = 1.50 \space moles + 3.50 \space moles = 5.00 \space moles$
3. Calculate the value of $V_2$:
$\frac{8.00 \space L}{1.50 \space moles} \times 5.00 \space mole = 26.7 \space L$
