Answer
The final volume is equal to 4.00 L
Work Step by Step
1. Using Avogadro's law, solve for "$V_2$":
$\frac{V_1}{n_1} = \frac{V_2}{n_2}$
- Multiply both sides by "$n_2$"
$\frac{V_1}{n_1} \times n_2 = {V_2}$
2. Since one-half of the Ne atoms escaped, the final number of moles is equal to "$\frac{1}{2} \times n_1$".
$n_2 = \frac{1}{2} \times n_1$
$n_2 = \frac{1}{2} \times 1.50 \space moles = 0.750 \space mole$
3. Calculate the value of $V_2$:
$\frac{8.00 \space L}{1.50 \space moles} \times 0.750 \space mole = 4.00 \space L$
