Answer
289 K
Work Step by Step
Let $T_{1} = 55^{o}C + 273 K = 328 K$, $P_{1} = 965 torr$, $P_{2} = 850 torr$ $T_{2} = ?$,
Using Gay Lussac's Law, we have:
$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$
$\frac{965 torr}{328 K} = \frac{850 torr}{T_{2}}$
$T_{2} = \frac{850 torr}{965 torr}$ x 328 K
= 289 K
