Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 8 - Section 8.3 - Temperature and Volume (Charles's Law) - Questions and Problems - Page 265: 8.27b

Answer

4885.06 mL

Work Step by Step

Let $T_{1} = 75^{o}C + 273 K = 348 K$, $V_{1} = 2500 mL$, $T_{2} = 680 K$, $V_{2} = ?$ Using Charles's Law, we have: $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ $\frac{2500 mL}{348 K} = \frac{V_{2}}{680 K}$ $V_{2} = \frac{680 K}{348 K}$ x 2500 mL = 4885.06 mL
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