Answer
300 L
Work Step by Step
Let $P_{1}$ = 15 atm , $V_{1}$ = 20 L, $P_{2}$ = 1 atm & $V_{2}$ = ?
Using gas Law Equation $P_{1}V_{1}=P_{2}V_{2}$, we have:
15 atm x 20 L = 1 atm x $V_{2}$
$V_{2}$ = 15 atm / 1 atm x 20 L
= 300 L
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