Answer
5240 mmHg
Work Step by Step
$V_{1}$ = 10.0 L
$p_{1}$ = 655 mmHg
$V_{2}$ = 1250 mL = 1.25 L
According to Boyle's law, $p_{1}V_{1} = p_{2}V_{2}$
This implies that $p_{2}$ = $\frac{p_{1}V_{1}}{V_{2}}$ = $\frac{655 mmHg\times10.0 L}{1.25 L}$ = 5240 mmHg.
