Answer
The balanced equation for the reaction is:
$F_2(g) + 2HCl(g) --\gt Cl_2(g) + 2HF(g)$
Work Step by Step
1. As we have determined in 7.80a, the reactants are: $F_2$ and $HCl$, and the products are : $Cl_2$ and $HF$.
- Write the unbalanced equation:
$F_2(g) + HCl(g) --\gt Cl_2(g) + HF(g)$
2. Balance the number of chlorine atoms, by putting a "2" as the coefficient of $HCl$:
$F_2(g) + 2HCl(g) --\gt Cl_2(g) + HF(g)$
3. Balance the number of fluorine atoms, by putting a "2" as the coefficient of $HF$:
$F_2(g) + 2HCl(g) --\gt Cl_2(g) + 2HF(g)$
- The equation is balanced.