Answer
The balanced equation for the reaction is:
$2HI(g) --\gt H_2(g) + I_2(g)$
Work Step by Step
1. As we have determined in 7.78a, the reactant is: $HI$, and the products are : $H_2$ and $I_2$.
- Write the unbalanced equation:
$HI(g) --\gt H_2(g) + I_2(g)$
2. Balance the number of iodine and hydrogen atoms, by putting a "2" as the coefficient of $HI$:
$2HI(g) --\gt H_2(g) + I_2(g)$
- The equation is balanced.
