Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 7 - Section 7.8 - Energy in Chemical Reactions - Understanding the Concepts - Page 247: 7.73d

Answer

A total of 6.8 moles of dipyrithione $(C_{10}H_8N_2O_2S_2)$ contains $8.2 \times 10^{24}$ atoms of $N$.

Work Step by Step

1. Find the conversion factors. According to the subscript for "N": 1 mole $C_{10}H_8N_2O_2S_2$ = 2 moles $N$ $\frac{ 1 \space mole \space C_{10}H_8N_2O_2S_2}{ 2 \space moles \space N}$ and $\frac{ 2 \space moles \space N}{ 1 \space mole \space C_{10}H_8N_2O_2S_2}$ Avogadro's number: $6.022 \times 10^{23}$ atoms = $1$ mole 2. Calculate the amount o dipyrithione moles: $8.2 \times 10^{24} \space atoms \space N \times \frac{1 \space mole}{6.022 \times 10^{23} \space atoms} \times \frac{ 1 \space mole \space C_{10}H_8N_2O_2S_2}{ 2 \space moles \space N} = $ $6.8$ moles $C_{10}H_8N_2O_2S_2$
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