Answer
A total of 6.8 moles of dipyrithione $(C_{10}H_8N_2O_2S_2)$ contains $8.2 \times 10^{24}$ atoms of $N$.
Work Step by Step
1. Find the conversion factors.
According to the subscript for "N":
1 mole $C_{10}H_8N_2O_2S_2$ = 2 moles $N$
$\frac{ 1 \space mole \space C_{10}H_8N_2O_2S_2}{ 2 \space moles \space N}$ and $\frac{ 2 \space moles \space N}{ 1 \space mole \space C_{10}H_8N_2O_2S_2}$
Avogadro's number: $6.022 \times 10^{23}$ atoms = $1$ mole
2. Calculate the amount o dipyrithione moles:
$8.2 \times 10^{24} \space atoms \space N \times \frac{1 \space mole}{6.022 \times 10^{23} \space atoms} \times \frac{ 1 \space mole \space C_{10}H_8N_2O_2S_2}{ 2 \space moles \space N} = $
$6.8$ moles $C_{10}H_8N_2O_2S_2$