Answer
Balanced chemical equation:
$C_5H_{12}(g) + 8O_2(g) --\gt 5CO_2(g) + 6H_2O(g)$
Work Step by Step
1. Identify the products and reactants:
Reactants: $C_5H_{12}$ and $O_2$
Products: $CO_2$ and $H_2O$
2. Write the unbalanced equation:
$C_5H_{12}(g) + O_2(g) --\gt CO_2(g) + H_2O(g)$
3. Balance the number of carbon atoms:
$C_5H_{12}(g) + O_2(g) --\gt 5 CO_2(g) + H_2O(g)$
4. Balance the number of hydrogen atoms:
$C_5H_{12}(g) + O_2(g) --\gt 5CO_2(g) + 6H_2O(g)$
5. There is a total of 16 oxygen atoms on the products side. Balance the number of $O$ atoms:
$C_5H_{12}(g) + 8O_2(g) --\gt 5CO_2(g) + 6H_2O(g)$
