Answer
The molar mass for $C_{19}H_{20}FNO_3$ is equal to 329.4 g
Work Step by Step
1. Identify the molar mass for each element in this compound:
$C: 12.01$ g
$H: 1.01$ g
$F: 19.00$g
$N: 14.01$ g
$O: 16.00$ g
2. Multiply each one of them by their respective subscript number:
$C: 12.01$ g * 19 =228.2 g
$H: 1.01$ g * 20 = 20.2 g
$F: 19.00$g *
$N: 14.01$ g
$O: 16.00$ g * 3 = 48.00 g
3. Calculate the total sum of these values:
$228.2g + 20.2g + 19.00g + 14.01g + 48.00g = 329.4g$
