Answer
The molar mass for $KH_2PO_4$ is equal to 136.09 g
Work Step by Step
1. Find the molar mass for each element in this compound:
$K: 39.10g$
$H: 1.008g$
$P: 30.97g$
$O: 16.00g$
2. Multiply each one of them by their respective subscript number:
$K: 39.10g $
$H: 1.008g * 2= 2.016g $
$P: 30.97g $
$O: 16.00g * 4= 64.00g$
3. Calculate the total sum of these values:
$39.10g + 2.016g + 30.97g + 64.00g = 136.09g$
