Answer
The molar mass for $Mg_3(PO_4)_2$ is equal to 262.9 g
Work Step by Step
1. Find the molar mass for each element in this compound:
$Mg: 24.31g$
$P: 30.97g$
$O: 16.00g$
2. Multiply each one of them by their respective subscript number. For the elements that are enclosed in brackets, also multiply them by the subscript of the brackets:
$Mg: 24.31g * 3= 72.93g $
$P: 30.97g * 2 = 61.94g $
$O: 16.00g * 4 * 2 = 128.0g$
3. Calculate the total sum of these values:
$72.93g + 61.94g + 128.0g = 262.9g$
