Answer
The molar mass for $(NH_4)_2CO_3$ is equal to 96.09g
Work Step by Step
1. Identify the molar mass for each element in this compound:
$N: 14.01g$
$H: 1.008g$
$C: 12.01g$
$O: 16.00g$
2. Multiply each one of them by their respective subscript number. For the elements that are enclosed in brackets, also multiply them by the subscript of the brackets:
$N: 14.01g * 2 = 28.02g$
$H: 1.008g * 4 * 2= 8.064g$
$C: 12.01g $
$O: 16.00g * 3= 48.00g$
3. Calculate the total sum of these values:
$28.02g + 8.064g + 12.01g + 48.00g = 96.09g$
