Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 3 - Section 3.6 - Specific Heat - Study Check 3.7 - Page 75: 1

Answer

25 kcal

Work Step by Step

$\Delta T = 67^{o}C - 22^{o}C = 45^{o}C$ cal = mass x $\Delta T$ x SH = 560 g x $45^{o}C$ x 1 cal / g $^{o}C$ = 25200 cal 1 kcal = 1000 cal 25200 cal x 1 kcal / 1000 cal = 25.2 kcal
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.