Answer
$$V_{olive \space oil} = 1.2 \times 10^3 \space cm^3$$
Work Step by Step
1. Calculate the mass of 1.50 L of gasoline.
According to the Table 2.9, the density of gasoline is equal to 0.74 g/mL
Knowing that 1 L = 1000 mL
$$m_{gasoline} = 1.50 \space L \times \frac{1000 \space mL}{1 \space L} \times \frac{0.74 \space g}{1 \space mL} = 1.1 \times 10^3 \space g$$
2. Find the volume of olive oil that has the same mass:
According to the Table 2.9, the density of olive oil is equal to 0.92 g/mL
Knowing that 1 $cm^3$ = 1 mL
$$V_{olive \space oil} = 1.1 \times 10^3 \space g \times \frac{1 \space mL}{0.92 \space g} \times \frac{1 \space cm^3}{1 \space mL} $$ $$V_{olive \space oil} = 1.2 \times 10^3 \space cm^3$$
