Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 2 - Section 2.6 - Problem Solving Using Unit Conversion - Questions and Problems - Page 45: 2.54e

Answer

$$4.03 \space oz \space used$$

Work Step by Step

1. Identify the equalities and conversion factors that we will use to solve this problem: $$8\% \space used = 100 \% \space total$$ $$1 \space lb = 16 \space oz*$$ $$1 \space kg = 2.20 \space lb*$$ * Check Table 2.7 (Page 38) 2. Solve the problem using multiple conversion factors: $$1.43 \space kg \space total \times \frac{8\% used}{100\% total} \times \frac{2.20 \space lb}{1 \space kg} \times \frac{16 \space oz}{1 \space lb} = 4.02688 \space oz \space used$$ - Rounding off to 3 significant figures: $$4.03 \space oz \space used$$
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