Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 6 - Sections 6.1-6.10 - Exercises - Problems by Topic: 83a

Answer

$\Delta$$H^{\circ}_{f}$$=-45.9 kJ/mol$

Work Step by Step

$\frac{1}{2}$$N_{2}(g)$$+$$\frac{3}{2}$$H_{2}(g)$$->NH_{3}(g)$
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