Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 6 - Sections 6.1-6.10 - Exercises - Problems by Topic: 60

Answer

$-267 kJ$$\times\frac{1 mol CH_{4}}{-802.3 kJ}\times\frac{16.0423 CH_{4}}{1 mol CH_{4}}$$=5.34 g$ $CH_{4}$

Work Step by Step

Use the enthalpy of reaction as a conversion factor in order to convert from kilojoules to moles of methane. Then use the molar mass of methane to convert from moles to grams of methane.
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