## Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall

# Chapter 6 - Sections 6.1-6.10 - Exercises - Problems by Topic: 36c

#### Answer

$745 kWh$$\times\frac{3.60\times10^{6}}{1 kWh}$$\times\frac{1 Cal}{4184J}$$=6.41\times10^{6} Cal$

#### Work Step by Step

Use a conversion factor to convert from kilowatt-hours to joules. Then convert joules into Calories.

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