Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic: 59

Answer

$37$ $g$ $NaNO_{3}$

Work Step by Step

Use molarity as a conversion factor in order to convert liters into moles. The use molar mass to convert from moles into grams. $400.0\times10^{-3}L$ $NaNO_{3}$ $\times\frac{1.1 mol NaNO_{3}}{1 L NaNO_{3}}$ $\times\frac{84.9947 g NaNO_{3}}{1 mol NaNO_{3}}$ $=37$ $g$ $NaNO_{3}$
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