# Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic: 58a

$2.25$ $L$ $C_{2}H_{6}O$

#### Work Step by Step

Use molarity as a conversion factor in order to convert moles into liters. $0.45$$mols$$C_{2}H_{6}O$$\times\frac{1 L C_{2}H_{6}O}{0.200 mol C_{2}H_{6}O}$$=2.25$$L$ $C_{2}H_{6}O$

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