Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic: 58a


$2.25$ $L$ $C_{2}H_{6}O$

Work Step by Step

Use molarity as a conversion factor in order to convert moles into liters. $0.45$$mols$$C_{2}H_{6}O$$\times\frac{1 L C_{2}H_{6}O}{0.200 mol C_{2}H_{6}O}$$=2.25$$L$ $C_{2}H_{6}O$
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