Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic: 57c

Answer

$0.211$ $mols$ $KCl$

Work Step by Step

Use molarity as a conversion factor in order to convert liters into moles. $114\times10^{-3}$$L$$KCl$$\times\frac{1.85 L KCl}{1 mol KCl}$$=0.211$ $mols$ $KCl$
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