# Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic: 54a

$0.062M$

#### Work Step by Step

To find the molarity we divide the number of moles of solute by the liters of solution. $M= \frac{Moles\ solute}{Liters\ solution}$ So for this problem we get: $\frac{0.38mol\ LiNO_{3}}{6.14L}= 0.062M$

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