Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic: 41b

Answer

$7 mol$ $TiCl_4$

Work Step by Step

Choose the limiting reactant to determine how much $TiCl_{4}$ is produced. $7$ $mol$ $Ti(avaliable)$ $17 mol$ $Cl_2$$\times\frac{1 mol TiCL_4}{2 mol Cl_{2}}$ $=8.5$ $mol$ $Ti (needed)$ Ti is the limiting reagent. $7 mol$ $Ti$$\times\frac{1 mol TiCL_4}{1molTi}$ $=7 mol$ $TiCl_4$ can be produced
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