# Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic: 41b

$7 mol$ $TiCl_4$

#### Work Step by Step

Choose the limiting reactant to determine how much $TiCl_{4}$ is produced. $7$ $mol$ $Ti(avaliable)$ $17 mol$ $Cl_2$$\times\frac{1 mol TiCL_4}{2 mol Cl_{2}} =8.5 mol Ti (needed) Ti is the limiting reagent. 7 mol Ti$$\times\frac{1 mol TiCL_4}{1molTi}$ $=7 mol$ $TiCl_4$ can be produced

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