## Chemistry: A Molecular Approach (3rd Edition)

Determine the limiting reactant. Choose one of the reactants and determine how much we need compared to how much is available. We choose to compare Al. $16$ $mol$ $Al (avaliable)$ $13 mol$ $O_{2}$$\times\frac{4 mol Al}{3 mol O_{2}}$ $=17$ $mol$ $Al (needed)$