Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic: 37c

Answer

$Br_{2}$ is the limiting reactant.

Work Step by Step

Determine the limiting reactant. Choose one of the reactants and determine how much we need compared to how much is available. We choose to compare Na. $2.5$ $mol$ $Na (avaliable)$ $1 mol$ $Br_{2}$$\times\frac{2 mol Na}{1 mol Br_{2}}$ $=2$ $mol$ $Na (needed)$

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