Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic: 83c

Answer

$1.4g\ Na$

Work Step by Step

Divide the compound by its molar mass to get the number of moles of the compound. Multiply by the ratio of moles of the compound to moles of sodium to get the number of moles of sodium. Multiply by the molar mass of sodium ($22.99\frac{g}{mol}$) to get the mass of sodium. $8.5g\ NaC_{7}H_{5}O_{2}\times\frac{1mol\ NaC_{7}H_{5}O_{2}}{144.103g\ NaC_{7}H_{5}O_{2}}\times\frac{1mol\ Na}{1mol\ NaC_{7}H_{5}O_{2}}\times\frac{22.99g\ Na}{1mol\ Na}= 1.4g\ Na$
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