Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 132: 70

Answer

$1.2\times10^{18}\,units$

Work Step by Step

Mass in grams of NaCl= 0.12 mg=$0.12\times10^{-3}g$ Formula mass of NaCl= 58.44 g/mol Number of moles of NaCl=$\frac{0.12\times10^{-3}g}{58.44g/mol}=2.0534\times10^{-6}\,mol$ Number of formula units= $2.0534\times10^{-6}\,mol\times\frac{6.022\times10^{23}}{1\,mol}=1.2\times10^{18}\,units$
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