Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 132: 68c

Answer

$2.992\times10^{-23}g\ H_{2}O$

Work Step by Step

Divide the number of molecules by Avagadro's number to get the number of moles. Multiply this number by the molar mass of the compound to get the mass of the sample. $1molecule\ H_{2}O\times\frac{1mol}{6.022\times10^{23}molecules}\times\frac{18.0153g\ H_{2}O}{1mol\ H_{2}O}= 2.992\times10^{-23}g\ H_{2}O$
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