Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic: 65c

Answer

$4.16\times10^{23}\ molecules$

Work Step by Step

Convert grams into moles using the molar mass then multiply by avagadro's number to get the number of molecules. $22.1g\ O_{2}\times\frac{1mol\ O_{2}}{32.00g\ O_{2}}\times\frac{6.022\times10^{23}\ molecules}{1\ mol}= 4.16\times10^{23}\ molecules$
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