Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 132: 65a

Answer

$2.2\times10^{23}\ molecules$

Work Step by Step

Convert grams into moles using the molar mass then multiply by avagadro's number to get the number of molecules. $6.5g\ H_{2}O\times\frac{1mol\ H_{2}O}{18.015g\ H_{2}O}\times\frac{6.022\times10^{23}\ molecules}{1\ mol}= 2.2\times10^{23}\ molecules$
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